-16x^2-19x+332=0

Solution for -16x^2-19x+332=0 equation:

-16x^2-19x+332=0

a = -16; b = -19; c = +332;
Δ = b2-4ac
Δ = -192-4·(-16)·332
Δ = 21609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21609}=147$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-147}{2*-16}=\frac{-128}{-32}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+147}{2*-16}=\frac{166}{-32}
=-5+3/16
$